15x^2-21x=19

Solution for 15x^2-21x=19 equation:

15x^2-21x=19

We move all terms to the left:

15x^2-21x-(19)=0

a = 15; b = -21; c = -19;
Δ = b2-4ac
Δ = -212-4·15·(-19)
Δ = 1581
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{1581}}{2*15}=\frac{21-\sqrt{1581}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{1581}}{2*15}=\frac{21+\sqrt{1581}}{30}
$